# Line slope calculator 2x+4y=40

**Straight line given by points A[0; 10] and B[4; 8]**

## Calculation:

**Slope-intercept form of line:**y = -0.5x+10

**Canonical form of the line equation:**2x+4y-40 = 0

**Parametric form of the line equation:**

x = 4t

y = -2t+10 ; t ∈ R

**Slope:**m = -0.5

**Slope angle of line: φ =**-26°33'54″ = -0.4636 rad

**X intercept:**x

_{0}= 20

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 8.9443

**The length of the segment AB: |AB| =**4.4721

**Vector: AB =**(4; -2)

**Normal vector: n =**(2; 4)

**Midpoint of the segment AB: M =**[2; 9]

**Perpendicular Bisector equation:**4x-2y+10 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (4; 8) ; |OB| = 8.9443**

**Scalar product OA .OB = 80**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**